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(I) A centrifuge accelerates uniformly from rest to 15,000 rpm in 240 s. Through how many revolutions did it turn in this time

Respuesta :

Answer:

θ = ω0 t + 1/2 ω t^2 = 1/2 α t^2          since it starts from rest

α = (15000 / 60) / 240 = 250 / 240 = 1.04 rev/sec^2

Note that α is in rev/sec^2

T(otal)  = 1/2 * 1.04 * 240^2 = 30,000 revolutions

Check:

Average RPM = (15000/2) = 7500 rev/min = 125 / sec

125 / sec * 240 sec = 30,000 rev

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