Respuesta :
Question:-
solve: (x+2)(5x-1)=0
Answer:-
x = 1/5
x = -2
Explanation:-
=> (x+2)(5x-1) = 0
=> x(5x-1) + 2(5x-1) = 0
=> 5x²- x + 10x - 2 = 0
=> 5x² + 9x - 2 = 0
- Plug them into quadratic formula.
=> x = -9 ± √9²-4×5(-2) / 2×5 = -9 ± 11/10
- To solve for the unknown variable, separate into two equations.... One with a plus and the other with a minus.
=> x = -9 + 11/10
=> x = -9 - 11/10
- Rearrange and isolate variables and find each solution.
x = 1/5
x = -2
The solution to the given quadratic equation is;
x = -2 and x = 1/5
Roots of quadratic Equation
We are given the quadratic function;
(x + 2)(5x - 1) = 0
In quadratic functions, when it is expressed as;
(x + a)(x - b) = 0, what this means is that the factors of the quadratic equation or polynomial are; (x + a) and (x - b)
What that means is that the roots will be gotten from;
(x + a) = 0 and (x - b) = 0
Thus, applying the concept above on roots of a polynomial to our question, we have;
(x + 2) = 0 and 5x - 1 = 0
Solving them gives us;
x = -2 and x = 1/5
Read more on roots of quadratic equation at; https://brainly.com/question/8649555