Find the diagonal of the rectangular solid.
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Answer:
5√2 feet or
7.07 feet to the nearest hundredth.
Step-by-step explanation:
First you need to find the length of a diagonal across the base of the solid.
x^2 = 5^2 + 4^2 = 41
so x = √41.
Now the diagonal of the solid is:
d^2 = 3^2 + (√41)^2 = 9 + 41
d^2 = 50
d = √50 = 5√2 ft.
Answer:
5√2
Step-by-step explanation:
(Diagonal of the floor)² = 5² + 4² = 25 + 16 = 41
Diagonal of the rectangular solid)² = (Diagonal of the floor)² + 3²
= 41 + 9 = 50
Diagonal of the rectangular solid = [tex]\sqrt{50} = \sqrt{2*5*5}=5\sqrt{2}[/tex]