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We are given –

  • Initial Volume, [tex]\bf V_1 [/tex] = 21 mL
  • Initial Pressure, [tex]\bf P_1[/tex] = 1.7 atm
  • Final Pressure, [tex]\bf P_2[/tex] = 3.9 atm
  • Final Volume, [tex]\bf V_2[/tex] =?

Using Boyle's law–

[tex]\qquad[/tex] [tex]\purple{\twoheadrightarrow\sf P_1V_1=P_2V_2}[/tex]

[tex]\qquad[/tex] [tex]\twoheadrightarrow\sf 1.7 \times 21 = 3.9 \times V_2 [/tex]

[tex]\qquad[/tex] [tex]\twoheadrightarrow\sf V_2 \times 3.9 = 35.7[/tex]

[tex]\qquad[/tex] [tex]\twoheadrightarrow\sf V_2 = \dfrac{35.7}{3.9}[/tex]

[tex]\qquad[/tex] [tex]\purple{\twoheadrightarrow\sf V_2 = 9.15\: mL}[/tex]

  • Henceforth, New /Final volume will be 9.15 mL.

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