contestada

Two blocks with masses 2.00 kg and 4.00 kg are placed side-by-side on a frictionless horizontal surface. A horizontal force with a magnitude of 5.20 N is applied to the 2.00-kg block perpendicular to its surface. What is the magnitude of the force on the 4.00-kg block?
a. 2.60
b. 3.11
c. 3.47
d. 3.89

Respuesta :

onyebuchinnaji

The magnitude of the force on the 4.00-kg block is 3.47 N.

The given parameters:

  • Mass of first block, m1 = 2 kg
  • Mass of second block, m2 = 4 kg
  • Horizontal force, F = 5.2 N

Acceleration of both blocks;

  • The acceleration of both blocks is calculated by applying Newton's second law of motion.

[tex]a = \frac{F}{m_1 + m_2} \\\\a = \frac{5.2}{2 + 4} \\\\a = \frac{5.2}{6} \\\\a = 0.867 \ m/s^2[/tex]

The magnitude of the force on the 4.00-kg block is calculated as follows;

F = ma

F = 4 x 0.867

F = 3.47 N

Learn more about Newton's second law of motion here: https://brainly.com/question/3999427

Otras preguntas