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A car weighing 15,680 N and moving at 20.0 m/s is acted upon by the brakes. The brakes apply a 650 N force until the car is slowed to a speed of 5.0 m/s.

What is the change in the car's momentum? Δp = _ kgm/s

Respuesta :

mickymike92

The change in momentum, Δp, of the body is 23520 Kgm/s

Momentum

  • The momentum of a body is defined as the product of its mass and velocity

Momentum, p = m×v

Change in momentum

Change in momentum is equal to the final momentum minus the intiala momentum

Change in momentum = mv - mu

Mass of car = weight/g

where g = 10 m/s^2

Mass of car = 15680/10

Mass of car = 1568 Kg

Change in momentum = 1568 Kg × 20 - 1568 Kg × 5

Change in momentum, Δp = 23520 Kgm/s

Therefore, the change in momentum, Δp, of the body is 23520 Kgm/s

Learn more about momentum at: https://brainly.com/question/7538238

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