Respuesta :

samueladesida43

The temperature of 16-gram sample of oxygen gas with a volume of 11.2 liters at standard pressure is 272.83K.

USING IDEAL GAS LAW:

The volume of an ideal gas can be calculated using the ideal gas law equation:

PV = nRT

Where;

  • P = pressure
  • V = volume
  • n = no. of moles
  • R = gas law constant
  • T = temperature

  1. no. of moles (n) = 16g/32g/mol = 0.5moles
  2. R = 0.0821 L/atmmolK
  3. V = 11.2L
  4. P = 1atm

1 × 11.2 = 0.5 × 0.0821 × T

11.2 = 0.04105T

T = 11.2/0.04105

T = 272.83K

Therefore, the temperature of 16-gram sample of oxygen gas with a volume of 11.2 liters at standard pressure is 272.83K.

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