Answer:
[tex](n^2+11n+25)\div( n+5)=n+6-\frac{5}{n+5}[/tex] or [tex]n+6,R5[/tex]
Step-by-step explanation:
Synthetic division:
-5 | 1 11 25
____-5 -30
1 6 | -5
Therefore, [tex](n^2+11n+25)\div( n+5)=n+6-\frac{5}{n+5}[/tex] or [tex]n+6,_$R$5[/tex]
Long division:
n+5 | n² + 11n + 25
- n² + 5n____ <-- n
6n + 25
- 6n + 30 <-- 6
-5 | n+6
Therefore, [tex](n^2+11n+25)\div( n+5)=n+6-\frac{5}{n+5}[/tex] or [tex]n+6,_$R$5[/tex]
