Respuesta :

Answer:  54, 55, 56, 57

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Work Shown:

  • x = first integer
  • x+1 = second integer
  • x+2 = third integer
  • x+3 = fourth integer

Sum the integers to get 222

(first)+(second)+(third)+(fourth) = 222

(x)+(x+1)+(x+2)+(x+3) = 222

4x+6 = 222

4x = 222-6

4x = 216

x = 216/4

x = 54 is the first integer

x+1 = 54+1 = 55 is the second integer

x+2 = 54+2 = 56 is the third integer

x+3 = 54+3 = 57 is the fourth integer

The sequence is 54, 55, 56, 57

Check:

54+55+56+57 = 222