What is the equation of the following line? Be sure to scroll down first to see
all answer options.
(-3, 1)
(0,0)
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-1/3x
We can find the straight line equation using this formula,
[tex]\frac{y-y1}{y2-y1} = \frac{x-x1}{x2-x1}[/tex]
Insert all we know inside the formula,
[tex]\frac{y-1}{0-1} = \frac{x-(-3)}{0-(-3)}\\\frac{y-1}{-1} = \frac{x +3}{3}\\[/tex]
Use cross multiplication,
3(y - 1) = -1(x + 3)\
3y - 3 = -x - 3
3y = -x - 3 + 3
3y = -x
y = -1/3x
The correct equation is y = -1/3x