Respuesta :
Answer:
[tex]\huge\boxed{\sf 15.75\ moles }[/tex]
Explanation:
Given reaction is:
3X + 2Y → 5C + 4D
In this reaction, we have:
For 3 moles of X, 4 moles of D
So,
4D = 3X
Divide both sides by 4
D = 3X/4
Multiply both sides by 21
21D = 3X/4 × 21
21D = 3*21X/4
21D = 63X/4
21D = 15.75X
So, to produce 21 moles of D, we need 15.75 moles of X.
[tex]\rule[225]{225}{2}[/tex]
Hope this helped!
~AH1807
[tex]\huge \tt༆ Answer ༄[/tex]
According to given equation,
[tex]{ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:3 \: moles \: X \rightarrow \: 4 \: moles \: D[/tex]
Now, let's use simple unitary method ~
[tex]{ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \: \dfrac{3}{4} \: moles \: X \rightarrow \: 1 \: moles \: D[/tex]
[tex]{ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \: \dfrac{3}{4} \times 21 \: moles \: X \rightarrow 21 \: moles \: D[/tex]
[tex]{ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:15.75 \: moles \: X \rightarrow 21 \: moles \: D[/tex]
Therefore, request moles of X is 15.75 moles !