caitlinw01 caitlinw01
  • 13-01-2022
  • Mathematics
contestada

I need to solve and find x. 4x+15<40

Respuesta :

jtm2588
jtm2588 jtm2588
  • 13-01-2022

Answer:

[tex]x<6.25[/tex] or [tex]x< 6 \frac{1}{4}[/tex]

Step-by-step explanation:

4x + 15 < 40

Subtract 15 from both sides

4x + 15 - 15 < 40 - 15

4x < 25

Divide both sides by 4

4x/4 < 25/4

x < 6.25

or

x < 6 1/4

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