The horizontal component of the force is 173.2 N.
The vertical component of the force is 100 N.
The given parameters:
The horizontal component of the force is calculated as follows;
[tex]F_x = Fcos(\theta)\\\\ F_x = 200 \times cos(30)\\\\ F_x = 173.2 \ N[/tex]
The vertical component of the force is calculated as follows;
[tex]F_y =F sin(\theta)\\\\ F_y= 200 \times sin(30)\\\\ F_y = 100 \ N[/tex]
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