This problem is providing the initial pressure and temperature inside a pressure cooker as 1 atm and 68 °F (20 °C) and the final temperature after cooking as 212 °F (100 °C) so that the final pressure is required and found to be 1.27 atm, according to the following:
Gay-Lussac's law:
In chemistry, gas laws have been widely used for the modelling of the pressure-volume-temperature-mole behavior of gases. In this particular case, we focus on a pressure-temperature relationship, firstly studied and proposed as the Gay-Lussac's law as a directly proportional relationship between temperature and pressure:
[tex]\frac{P_2}{T_2}= \frac{P_1}{T_1} [/tex]
Thus, we can solve for the final pressure, P2, via:
[tex]P_2= \frac{P_1T_2}{T_1} [/tex]
So we plug in the given data by making sure the temperatures are all in Kelvins:
[tex]P_2= \frac{1atm*373K}{293K}\\
\\
P_2=1.27atm[/tex]
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