Answer: Choice A. [tex]|x+6| < 10[/tex]
Explanation:
The rule is that stuff of the form [tex]|x| < k[/tex] becomes [tex]-k < x < k[/tex] where k is some positive number.
So we'll have these steps
[tex]|x+6| < 10\\\\-10 < x+6 < 10\\\\-10-6 < x+6-6 < 10-6\\\\-16 < x < 4\\\\[/tex]
In the third step, I subtracted 6 from all sides to isolate x.
The last step indicates we'll have open holes at -16 and 4, with shading in between. It visually tells the reader "x can be anything between -16 and 4, but can't be equal to either endpoint".
