Answer:
10,800 yd/mo
Step-by-step explanation:
[tex]\dfrac{9\text{ in}}{\text{min}}=\dfrac{9\text{ in}}{\text{min}}\times\dfrac{1\text{ yd}}{36\text{ in}}\times\dfrac{60\text{ min}}{1\text{ h}}\times\dfrac{24\text{ h}}{1\text{ da}}\times\dfrac{30\text{ da}}{1\text{ mo}}=\dfrac{(9)(60)(24)(30)}{36}\text{ yd/mo}\\\\=\boxed{10,\!800\text{ yd/mo}}[/tex]
