Respuesta :
The car that has the greater acceleration magnitude is car B
Torricelli's theorem can be used to calculate the magnitude of an object's acceleration when the value of time is not known:
[tex]v^{2} = v_{0}^{2} + 2a\Delta S[/tex]
Note that [tex]v\\[/tex] is the final velocity value, [tex]v_{0}[/tex] is the initial velocity value, [tex]a[/tex] is the acceleration value, and [tex]\Delta S[/tex] is the displacement.
Substituting the values given by the question in the formula, we have:
- CAR A
[tex]10^{2}= 0^{2}+2\times a \times 50[/tex]
[tex]100 = 100a[/tex]
[tex]a = 1m/s^{2}[/tex]
2. CAR B
[tex]20^{2} = 10^{2} + 2\times a \times 50[/tex]
[tex]400 = 100 + 100a[/tex]
[tex]100a=300[/tex]
[tex]a = 3m/s^{2}[/tex]
So, comparing the two acceleration calculated above, it is assumed that the car has the greater acceleration magnitude is car B with [tex]3m/s^{2}[/tex] comparing to [tex]1m/s^{2}[/tex] of the car A.
Learn more about acceleration magnitude in: brainly.com/question/11273796
