Answer:
See below
Step-by-step explanation:
Problem 6
[tex]tan\theta=\frac{opposite}{adjacent}[/tex]
[tex]tan67^\circ=\frac{x}{9}[/tex]
[tex]9tan67^\circ=x[/tex]
[tex]x=9tan67^\circ[/tex]
[tex]x\approx21.2[/tex]
Problem 7
[tex]sin\theta=\frac{opposite}{hypotenuse}[/tex]
[tex]sin37^\circ=\frac{9}{x}[/tex]
[tex]xsin37^\circ=9[/tex]
[tex]x=\frac{9}{sin37^\circ}[/tex]
[tex]x\approx14.95[/tex]
Problem 8
[tex]tan\theta=\frac{opposite}{adjacent}[/tex]
[tex]tan42^\circ=\frac{x}{13}[/tex]
[tex]13tan42^\circ=x[/tex]
[tex]x=13tan42^\circ[/tex]
[tex]x\approx11.71[/tex]
