Answer:
[tex] ZnSO_4 + Li_2CO_3 \longrightarrow ZnCO_3 + Li_2SO_4 [/tex]
Explanation:
Here a reaction is given to us and we need to balance the equation . The given reaction is ,
[tex] ZnSO_4 + Li_2CO_3 \longrightarrow ZnCO_3 + Li_2SO_4 [/tex]
So here , we can make a table as ,
[tex]\begin{array}{c|c} \\ LHS & RHS \\\\ Zn = 1 & Zn = 1 \\\\ SO_4 = 1 & SO_4 =1\\\\ Li = 2 & Li= 2 \\\\ CO_3 = 1 & CO_3 = 1 \end{array}[/tex]
We can see that the number of elements and ions is same on both LHS and RHS . Hence the reaction is already balanced .
Therefore the final reaction would be same as before that is ,
[tex] ZnSO_4 + Li_2CO_3 \longrightarrow ZnCO_3 + Li_2SO_4 [/tex]
I hope this helps .
