*The molality of a solution is calculated by taking the moles of solute and dividing by the kilograms of solvent* Basically if we had 1.00 mole of sucrose (it's about 342 3 grams) and proceeded to mix it into exactly 1.00 liter water. It would dissolve and make sugar water. We keep adding water, dissolving and stirring until all the solid was gone. We then made sure everything was well-mixed. What would be the molality of this solution? Notice that my one liter of water weighs 1000 grams (density of water = 1.00 g / mL and 1000 mL of water in a liter).
