Respuesta :
- Initial velocity=20m/s
- Final velocity=0m/s(As the car stops)
- Acceleration=-8m/s^2
- Distance=s=26m
We need to verify the thrid equation of kinematics here
[tex]\\ \tt\longmapsto v^2-u^2=2as[/tex]
[tex]\\ \tt\longmapsto 20^2=2(-8)s[/tex]
[tex]\\ \tt\longmapsto 400=-16s[/tex]
[tex]\\ \tt\longmapsto s=|400/-16|[/tex]
[tex]\\ \tt\longmapsto s=25m[/tex]
The squirrel has a good luck ,Car gets stopped just 1m away from the squirrel .
Explanation:
According to the Question
A squirrel runs out in front of a car moving at +20m/s ( initial speed u) . The driver slams on the brakes and begins decreasing at -8m/s² ( here the acceleration is acting in opposite directions of motion a )
When Squirrel was 26 metres ( Distance from the car initially )
Using Kinematic Equation
- v² = u² + 2as
On substituting the value we obtain
➥ 0² = 20² + 2 × -8 × s
➥ 0 = 400 - 16 × s
➥ -400 = -16 × s
➥ 400/16 = s
➥ 25 = s
So, the squirrel is 25 metres from the car .
