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A force of 128 lb is required to hold a spring stretched 2 ft beyond its natural length. How much work W is done in stretching it from its natural length to 9 inches beyond its natural length

Respuesta :

okpalawalter8

We have that the  workdone in stretching natural length to is mathematically given as

W=9/2lbft

Workdone in stretching natural length

Question Parameters:

  • A force of 128 lb is required to hold a spring stretched 2 ft beyond its natural length.
  • Stretching it from its natural length to 9 inches beyond its natural length

Generally the Hookes equation for the Force   is mathematically given as

F=Kx

Where

3.2lb=2ft*k

Thereofore

k=16

Force becomes

f=kx

f=16x

Hence

[tex]W=8[x^2]^{3/4}_{0}[/tex]

W=9/2lbft

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