Respuesta :
Answer:
58.92 g EDTA
Explanation:
315.1 mL = .3151 L
M = Moles / Liter
.3151 L x 0.5 mol EDTA x 374 g EDTA = 58.92 g EDTA
1 L EDTA 1 mol EDTA
The amount in grams of EDTA needed to make 315.1 mL of a 0.05 M is equal to 5.89 g.
Molar concentration
In a 0.05M solution, there are 0.05 moles of the substance per 1 liter, that is, in 315.1 ml we have:
[tex]\frac{0.05 mol}{xmol}= \frac{1000ml}{315.1ml}[/tex]
[tex]x = 0.016 mol[/tex]
Thus, 0.016 mol EDTA of is needed to prepare the solution.
Mass calculation
To calculate the mass in an amount of moles, we use the molar mass, so that:
[tex]m = MM \times mol[/tex]
[tex]m = 374 \times 0.016[/tex]
[tex]m = 5.89 g[/tex]
So, the amount in grams of EDTA needed to make 315.1 mL of a 0.05 M is equal to 5.89 g.
Learn more about mole calculation in: brainly.com/question/2845237
