The regular octagon has eight equal sides. Then the area of the regular octagon of side length be 4.6 is 102 ft².
It is a polygon that has eight equal sides. In a regular octagon, the opposite sides are parallel. And its diagonals are also equal and intersect at mid-point.
Given
A regular octagon has a radius of 6 ft and a side length of 4.6 ft.
We know the formula for the regular octagon.
Area of the regular octagon = 2(1 + [tex]\sqrt{2}[/tex]) a²
Where a be the side of a regular octagon.
Then the area of the regular octagon will be.
[tex]\rm Area = 2 (1+\sqrt{2} ) a^2\\\\Area = 2*(1 + 1.414) *4.6^2\\\\Area = 2 * (2.414)* 21.16\\\\Area = 102.16[/tex]
Thus, the area of the regular octagon of side length be 4.6 is 102 ft².
More about the regular octagon link is given below.
https://brainly.com/question/858868
