Fiona recorded the number of miles she biked each day last week as shown below. 4, 7, 4, 10, 5 The mean is given by m = 6. Which equation shows the variance for the number of miles Fiona biked last week? s squared = StartFraction (4 minus 6) squared (7 minus 6) squared (4 minus 6) squared (10 minus 6) squared (5 minus 6) squared Over 6 EndFraction Sigma = StartRoot StartFraction (4 minus 6) squared (7 minus 6) squared (4 minus 6) squared (10 minus 6) squared (5 minus 6) squared Over 5 EndFraction EndRoot s = StartRoot StartFraction (4 minus 6) squared (7 minus 6) squared (4 minus 6) squared (10 minus 6) squared (5 minus 6) squared Over 4 EndFraction EndRoot Sigma squared = StartFraction (4 minus 6) squared (7 minus 6) squared (4 minus 6) squared (10 minus 6) squared (5 minus 6) squared Over 5 EndFraction.

Respuesta :

Variance is average of squared error of observations from mean. The variance of given data is 5.2

How to calculate variance of a given data set?

Variance is average of squared error of observations from mean.

  • If the data set is composed of n elements,
  • its ith element is [tex]x_i[/tex] ,
  • and mean of the data set is [tex]\overline{x}[/tex] ,

then its variance is given as:

[tex]\sigma^2 = \dfrac{1}{n} \sum_{i=1}^n(x_i-\overline{x})^2[/tex]

The given data set is 4,7,4,10,5

Thus, n = 5 (total 5 observations (data values) )

Their mean is [tex]\overline{x} = 6[/tex] (it is taken as 'm', but for ease with formula, take it as [tex]\overline{x}[/tex] )

Thus, their variance is calculated as:

[tex]\sigma^2 = \dfrac{1}{n} \sum_{i=1}^n(x_i-\overline{x})^2 \\\\\sigma^2 = \dfrac{(4-6)^2 + (7-6)^2 + (4-6)^2 + (10-6)^2 +(5 - 6)^2}{5} \\\\\sigma^2 = \dfrac{4 + 1 + 4 + 16 + 1}{5} = \dfrac{26}{5} = 5.2[/tex]


Thus,

The variance of given data is 5.2

Learn more about variance here:

https://brainly.com/question/3699980

Answer:

d

Step-by-step explanation: