Using the Poisson distribution, it is found that the expected number of phone calls that pass through the switchboard in one minute is of 2.
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by:
[tex]P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}[/tex]
The parameters are:
In this problem, the mean is equals to 2 phone calls per minute, hence this is the expected number.
You can learn more about the Poisson distribution at https://brainly.com/question/13971530