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The volume occupied by 9 x 1023 molecules of nitrogen gas at STP is closest to
1.5 L
22.4 L
33.6 L
0.5 L​

Respuesta :

This problem is providing the number of molecules of nitrogen at STP and asks for the volume they take up. At the end, the result turns out to be 33.6 L according to the following.

Avogadro's law

In chemistry, gas laws are used to relate pressure, temperature, volume and moles as an indicator of the behavior of gases. Thus, since this problem provides the number of molecules of nitrogen gas at STP, standard pressure and temperature (1atm and 273K), one knows the Avogadro's law must be utilized.

In such a way, this law allows us to know that 1 mole of any substance is related to 6.022x10²³ particles and that 1 mole of the gas occupies 22.4 L at STP. Hence, we can find the volume with the following setup:

[tex]9x10^{23}molecules*\frac{1mol}{6.022x10^{23}molecules} *\frac{22.4L}{1mol} \\\\=33.5L[/tex]

Which can be rounded then to 33.6 L.

Learn more about ideal gases: brainly.com/question/8711877