How many grams of iron (Fe) would be needed to generate 5.25 g of hydrogen gas (H2)?
[tex]3Fe + 4H_2O -\ \textgreater \ 4H_2 + Fe_3O_4[/tex]
A) 109 g Fe
B) 146 g Fe
C) 214 g Fe
D) 2.00 g Fe

Respuesta :

Considering the given reaction, 109 g of Fe are needed to generate 5.25 g of H₂.

What is stoichiometry?

Stoichiometry refers to the relationship between the quantities of reactants and products before, during, and following chemical reactions.

  • Step 1: Write the balanced equation.

3 Fe + 4 H₂O ⇒ 4 H₂ + Fe₃O₄

  • Step 2: Calculate the mass of Fe needed to produce 5.25 g of H₂.

We will consider the following relationships.

  1. The molar mass of Fe is 55.85 g/mol.
  2. The molar ratio of Fe to H₂ is 3:4.
  3. The molar mass of H₂ is 2.02 g/mol.

[tex]5.25gH_2 \times \frac{1molH_2}{2.02gH_2} \times\frac{3molFe}{4molH_2} \times\frac{55.85gFe}{1molFe} = 109gFe[/tex]

Considering the given reaction, 109 g of Fe are needed to generate 5.25 g of H₂.

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