If (0.2)x = 2 and log 2 = 0.3010, then the value of x to the nearest tenth is:

(a) -10.0, (b) -0.5, (c) -0.4, (d) -0.2, (e) 10.0​

Respuesta :

Answer:

Solution:

(0.2)x = 2.

Taking log on both sides

log (0.2)x = log 2.

x log (0.2) = 0.3010, [since log 2 = 0.3010].

x log (2/10) = 0.3010.

x [log 2 - log 10] = 0.3010.

x [log 2 - 1] = 0.3010,[since log 10=1].

x [0.3010 -1] = 0.3010, [since log 2 = 0.3010].

x[-0.699] = 0.3010.

x = 0.3010/-0.699.

x = -0.4306….

x = -0.4 (nearest tenth)

Answer is option (c) -0.4

The value of x to the nearest tenth is -0.4

Logarithmic expression

Given the following expressions

(0.2)x = 2 and log 2 = 0.3010

Taking log of both sides of (0.2)x = 2

log (0.2)x = log 2.

x log (0.2) = 0.3010,

x [log 2 - log 10] = 0.3010.

Note that log2 2 = 1

x [log 2 - 1] = 0.3010

x [0.3010 -1] = 0.3010, [since log 2 = 0.3010].

x[-0.699] = 0.3010.

x = 0.3010/-0.699.

x = -0.4306

Hence the value of x to the nearest tenth is -0.4

Learn more on logarithm here: https://brainly.com/question/25710806

Answer is option (c) -0.4