PLEASE HELP !! with solution needed!!
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[tex] \looparrowright \sf13x + 2 = 4x + 38[/tex]
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[tex] \looparrowright \sf13x - 4x + 2 = 38[/tex]
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[tex] \looparrowright \sf9x + 2 = 38[/tex]
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[tex] \looparrowright \sf9x = 38 - 2[/tex]
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[tex] \looparrowright \sf9x = 36[/tex]
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[tex] \looparrowright \sf x = \dfrac{36}{9} [/tex]
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[tex] \looparrowright \sf x = 4[/tex]
Answer:
Step-by-step explanation:
[tex]13x + 2 = 4x + 38 \\ 13x - 4x = 38 - 2 \\ 9x = 36 \\ \frac{9x}{9} = \frac{36}{9} \\ x = 4 \\ [/tex]