What value of x satisfies this equation?
log2 (6x – 8) – log, 2^8=1
The value of x is?

Answer:
[tex]x=4[/tex]
Step-by-step explanation:
[tex]log_2(6x-8)-log_2(8)=1\\\\log_2(\frac{6x-8}{8})=1\\ \\\frac{6x-8}{8}=2\\ \\6x-8=16\\\\6x=24\\\\x=4[/tex]