Answer:
Frequency=0.39Hz
Explanation:
A pendulum completes 23 full cycles in 58 seconds
A pendulum completes 1 full cycle in 58/23=2.52 seconds
Time taken(t)=2.52 seconds
Now,
Frequency=1/time taken
Frequency=1/2.25
Frequency=0.39Hz
When a pendulum is observed to complete 23 full cycles in 58 seconds. then the period is 2.521739 and the frequency of the pendulum is 0.39655 S⁻¹
It can be defined as the number of cycles completed per second.It is represented in hertz and inversely proportional to the wavelength.
The frequency of a pendulum is the reciprocal of the time period can be given by the following relation
f = 1/T
where f is the frequency
T is the time period of the pendulum
As given in the problem that a pendulum is observed to complete 23 full cycles in 58 seconds
Then the number of cycles per second is known as the frequency
f = 23/58
f = 0.39655 S⁻¹
As the time period is reciprocal to the frequency
T= 1/f
T = 1/0.39655
T =2.521739
Thus, if 58 seconds pass before a pendulum completes 23 full cycles. then the pendulum's frequency would be 0.39655 S⁻¹, and its period would be 2.521739.
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