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What is the smallest number that has a remainder of 1, 2, and 3 when divided by 2, 3, and 4, respectively? Are there more numbers that have this property? ​

Respuesta :

abdullahmaryam540

Answer:

11 is the answer.

Step-by-step explanation:

11 and 23 are the answers.

Step-by-step explanation:

Multiple of 2 increase 1 =

[tex]3,5,7,9,11,13,15,17...[/tex]

Multiple of 3 increase 2 =

[tex]5,8,11,14,17...[/tex]

Multiple of 4 increase 3 =

[tex]7,11,15,19...[/tex]

Here, we can see the smallest number is 11

There are more numbers having this property such as 23.

[tex]23 \div 2 = 11...1[/tex]

[tex]23 \div 3 = 7...2[/tex]

[tex]23 \div 4 = 5...3[/tex]

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