Answer:
8.2 units
Step-by-step explanation:
Given that the only information for our triangle are 2 sides and 1 angle, we must use the Law of Cosines to find side BC
Recall the Law of Cosines
[tex]a^2=b^2+c^2-2bc\cdot cos(A)[/tex]
Identify angles and sides
[tex]m\angle A=23^\circ\\a=BC=?\\b=AC=14\\c=AB=6[/tex]
Solve for side "a"
[tex]a^2=b^2+c^2-2bc\cdot cos(A)\\\\a^2=14^2+6^2-2(14)(6)\cdot cos(23^\circ)\\\\a^2=196+36-168cos(23^\circ)\\\\a^2=222-168cos(23^\circ)\\\\a=\sqrt{222-168cos(23^\circ)}\\ \\a\approx8.2[/tex]
Therefore, the length of line segment BC is about 8.2 units
Answer:
the answer is 8.2 units
Step-by-step explanation:
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