Answer:
D) x=9 ; y=3√(3)
Step-by-step explanation:
[tex]Sin(30)=\cfrac{y}{6\sqrt{3} }[/tex]
[tex]\cfrac{18y}{6\sqrt{3}}=18\sin \left(30^{\circ \:}\right)[/tex]
[tex]\sqrt{3}y=9[/tex]
[tex]\cfrac{\sqrt{3}y}{\sqrt{3}}=\cfrac{9}{\sqrt{3}}[/tex]
[tex]y=3\sqrt{3}[/tex]
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[tex]Cos(30)=\cfrac{x}{6\sqrt{3} }[/tex]
[tex]\cfrac{18x}{6\sqrt{3}}=18\cos \left(30^{\circ \:}\right)[/tex]
[tex]\sqrt{3}x=9\sqrt{3}[/tex]
[tex]\cfrac{\sqrt{3}x}{\sqrt{3}}=\cfrac{9\sqrt{3}}{\sqrt{3}}[/tex]
[tex]x=9[/tex]
Therefore, x=9 and y=3√(3)
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