Using the permutation formula, as the order is important, it is found that 2520 distinct passwords can be made.
The order is important as abcde is a different password than edcba, hence the permutation formula is used.
The number of possible permutations of x elements from a set of n elements is given by:
[tex]P_{(n,x)} = \frac{n!}{(n-x)!}[/tex]
In this problem, 5 letters are chosen from a set of 7, hence:
[tex]P_{7,5} = \frac{7!}{(7-5)!} = 2520[/tex]
2520 distinct passwords can be made.
More can be learned about the permutation formula at https://brainly.com/question/25925367