The hourly wage of some Toyota automobile assembly line workers is being increased annually by the same percentage

If their wage went from $6.80 to $10.19 in 7 years what is the doubling time?

(nearest year)

Respuesta :

The doubling time of the hourly wage of the workers is an illustration of an exponential function that has a rate of 2

The doubling time of the wage is 4 years

How to determine the doubling time

A doubling function is represented as:

[tex]p = w \times 2^{\frac{x}{t}}[/tex]

Where:

  • p represents the final amount i.e. p = 10.19
  • w represents the initial amount i.e. w = 6.80
  • t represents the duration i.e. t = 7
  • x represents the doubling time

So, we have:

[tex]10.19 = 6.80 \times 2^{\frac{x}{7}}[/tex]

Divide both sides by 6.80

[tex]1.50 = 2^{\frac{x}{7}}[/tex]

Take the logarithm of both sides

[tex]\log(1.50) = \log(2^{\frac{x}{7}})[/tex]

Apply the law of logarithm

[tex]\log(1.50) = \frac{x}{7}}\log(2)[/tex]

Multiply both sides by 7

[tex]7 \times \log(1.50) = x\log(2)[/tex]

Divide both sides by log(2)

[tex]x = 7 \times \log(1.50) \div \log(2)[/tex]

[tex]x = 4.09[/tex]

Approximate

[tex]x \approx 4[/tex]

Hence, the doubling time is 4 years

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