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Two learners want to confirm the principle of conservation of momentum for an isolated system. Two trolleys, with identical dimensions, but masses m and 1/2m, with a spring- loaded plunger between them, are placed on a horizontal surface. When the spring is released, it takes trolley X only 0.5 s to reach the barrier, which is 100 mm away. Trolley Y takes the same time to cover 200 mm to the other barrier.

1. Calculate the average speeds of trolleys X and Y respectively.

2 Calculate the total momentum after the release of the spring.​

Two learners want to confirm the principle of conservation of momentum for an isolated system Two trolleys with identical dimensions but masses m and 12m with a class=

Respuesta :

mickymike92

Based on the principle of conservation of momentum;

  • average speed of A is 0.2 m/s
  • average speed of B is 0.4 m/s
  • the total momentum after the release of the spring is zero.

What is the principle of conservation of momentum?

The principle of conservation of momentum states that in an isolated system of colliding bodies, momentum is conserved.

This principle can be stated mathematically as:

  • momentum before collision = momentum after collision.

The average speed of each trolley is calculated using the formula:

  • average speed = total distance/total time taken

For Trolley A:

average speed = 100 mm/0.5 = 200 mm/s

average speed of A = 0.2 m/s

For Trolley B:

distance = 200 mm = 0.2 m

average speed = 0.2 m/0.5 s

average speed of B = 0.4 m/s

Momentum = mass × velocity

Assuming direction of motion of B is positive, direction of A is negative

Momentum of A = - m × 0.2 = -0.2m

Momentum of B = m/2 × 0.4 = 0.2 m

Total momentum = 0.2 m - 0.2 = 0

Therefore, the total momentum before and after the release of the spring is zero.

Learn more about law of conservation of momentum at: https://brainly.com/question/7538238

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