Respuesta :

Solution:

[tex]\small\bold{(x – 4)(x + 5) }[/tex]

[tex]\small\bold{ → x(x + 5) -4(x + 5) }[/tex]

[tex]\small\bold{→ x2 + 5x – 4x – 20 }[/tex]

[tex]\small\bold{ → x2 + x - 20 }[/tex]

Option (d) x2 + x - 20 is correct

FOIL

[tex] \mathbb{PROBLEM:}[/tex]

» Multiply: (x – 4)(x + 5)

  • (a) x² + 5x - 20
  • (b) x² - 4x - 20
  • (c) x² - x - 20
  • (d) + x - 20

[tex] \mathbb{ANSWER:}[/tex]

  • [tex]\tt \color{hotpink} \bold{{x}^{2} + x- 20}[/tex]

— — — — — — — — — —

Solution:

  • [tex]\tt \bold{ F} \to (x – 4)(x + 5) = \blue{ {x}^{2} }[/tex]

  • [tex] \tt \bold{O } \to (x – 4)(x + 5) = \blue{ 5x}[/tex]

  • [tex] \tt \bold{ I} \to(x – 4)(x + 5) = \blue{ -4x}[/tex]

  • [tex] \tt \bold{L } \to (x – 4)(x + 5) = \blue{ - 20} [/tex]

So,

[tex] \to \: \tt x {}^{2} + 5x - 4x - 20 \\ \tt \: = \underline{ \boxed{ \purple{ \tt{ {x}^{2} + x - 20 }}}}[/tex]

Hence, choice D is correct.

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