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What is the molality of a CaCl2 solution that contains 166.5 g CaCl2 and is dissolved in 3.5kg of water? 0.429 molal 47.6 molal 5.25 molal 1.50 molal

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Eduard22sly

The molality of the CaCl₂ solution given that 166.5 g of CaCl₂ dissolves in 3.5 Kg of water is 0.429 M

What is molality?

This is the defines as the mole of solute per unit mass (in Kilogram) of water.

Molality = mole / mass of water (in Kg)

How to determine the mole of CaCl₂

The mole of 166.5 g of CaCl₂ can be obtained as illustrated below:

  • Mass of CaCl₂ = 166.5 g
  • Molar mass of CaCl₂ = 40 + (35.5×2) = 111 g/mole
  • Mole of CaCl₂ = ?

Mole = mass / molar mass

Mole of CaCl₂ = 166.5 / 111

Mole of CaCl₂ = 1.5 moles

How to determine molality of the solution

The molality of the CaCl₂ solution can be obtained as illustrated below:

  • Mole of CaCl₂ = 1.5 moles
  • Mass of water = 3.5 Kg
  • Molality of CaCl₂ = ?

Molality = mole / mass of water (in Kg)

Molality of CaCl₂ = 1.5 / 3.5

Molality of CaCl₂ = 0.429 M

Thus, the molality of the solution is 0.429 M

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