The simplification of the expression (h² + 9·h - 1) × (-4·h + 3), involves the
multiplication of the terms. The error is therefore;
3. Calculating errors when distributing -1
How can the error in the calculation be found?
The expansion of (h² + 9·h - 1) × (-4·h + 3), is given as follows;
(h² + 9·h - 1) × (-4·h + 3) = -4·h³ + 3·h² - 36·h² + 27·h + 4·h - 3
Which gives;
-4·h³ - 33·h² + 31·h - 3
The calculation is therefore;
[tex]\begin{array}{|c|c|c|c|}&h^2&+9 \cdot h & -1\\-4 \cdot h&-4\cdot h^3&-36\cdot h^2 &4 \cdot h\\+3& 3 \cdot h^2&27 \cdot h&3\end{array}\right][/tex]
The error is therefore, in the distribution of the -1
The correct option is;
3. Calculating errors when distributing -1
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