Respuesta :

The terminal ray of an angle A passes through the origin

The value of csc(A) is -1.2

How to determine the cosine of angle A

The coordinates of the terminal ray is given as:

(x,y) = (-4,-6)

Start by calculating the length (L) of the hypotenuse

[tex]L = \sqrt{x^2 + y^2}[/tex]

So, we have:

[tex]L = \sqrt{(-4)^2 + (-6)^2}[/tex]

Evaluate the exponent

[tex]L = \sqrt{52}[/tex]

Evaluate the root

[tex]L = 7.2[/tex]

The sine of the angle A is then calculated as:

[tex]\sin(A) = \frac{-6}{7.2}[/tex]

The csc of the angle A is then calculated as:

[tex]\csc(A) = \frac{1}{\sin(A)}[/tex]

So, we have:

[tex]\csc(A) = \frac{7.2}{-6}[/tex]

[tex]\csc(A) = -1.2[/tex]

Hence, the value of csc(A) is -1.2

Read more about terminal rays at:

https://brainly.com/question/12121125