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A sample of sulfur dioxide (SO2) is initially at a temperature of 105C, a volume of 15 L, and a pressure of 1.5 atm. If the volume changes to 25 L and the temperature increases to 181C, what is the new pressure? Show your work.

Respuesta :

The new pressure is 1.08 atm

Gas laws

From the question, we are to determine the new pressure

Using the General gas equation,

[tex]\frac{P_{1}V_{1} }{T_{1}} = \frac{P_{2}V_{2} }{T_{2}}[/tex]

Where

  • P₁ is the initial pressure
  • V₁ is the initial volume
  • T₁ is the initial temperature
  • P₂ is the final pressure
  • V₂ is the final volume
  • T₂ is the final temperature

From the given information,

P₁ = 1.5 atm

V₁ = 15 L

T₁ = 105 C = 105 + 273.15 = 378.15 K

V₂ = 25 L

T₂ = 181 C = 181 + 273.15 = 454.15 K

P₂ = ?

Putting the parameters into the equation, we get

[tex]\frac{1.5 \times 15}{378.15} = \frac{P_{2} \times 25 }{454.15}[/tex]

[tex]P_{2}= \frac{1.5 \times 15 \times 454.15}{25 \times 378.15}[/tex]

P₂ = 1.08 atm

Hence, the new pressure is 1.08 atm

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