The percent yield is closest to 17%
The reaction between Li3N(s) and LiH(s) is given as:
[tex]Li_3N+3H_2\rightarrow 3LiH+NH_3[/tex]
Calculate the moles of Li3N
Moles = Mass/Molar mass
Moles = 70/35
Moles = 2 moles
From the reaction you can see that 1 mole of Li3N produce 3 moles of LiH, hence the moles of LiH is 6 moles
Determine the mass of LiH (theoretical yield)
Mass of LiH = 6 * 7.95
Mass of LiH = 47.7g
%yield = actual/theoretical * 100
%yield = 8/47.7 * 100
%yiels = 16.77%
Hence the percent yield is closest to 17%
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