The distribution of the animals in the coral reef is an illustration of probability
The most likely animal
The distribution of the animals is given as:
Blue fish = 3
Yellow fish = 7
Sea turtle = 1
Eels = 3
The animal with the highest frequency is the most likely animal.
Hence, the Yellow fish is the most likely animal.
Which is more likely?
From the question, we have:
Blue fish = 3
Eels = 3
Both animals have the same frequency.
This means that Riley has equal chance of seeing a blue fish and an eel.
The probability of seeing an animal with fins
The animal with fins are:
Blue fish = 3
Yellow fish = 7
So, the probability is:
[tex]p = \frac{3 + 7}{3 + 7 + 1 + 3}[/tex]
[tex]p = \frac{10}{14}[/tex]
Simplify
[tex]p = \frac 57[/tex]
Hence, the probability of seeing an animal with fins is 5/7
The least likely animal
The animal with the least frequency is:
Sea turtle = 1
So, the likelihood is:
[tex]p = \frac 1{14}[/tex]
Hence, the sea turtle has the least likelihood of 1/14
Animals with equal likelihood
The Blue fish and the Eels have the same frequency of 3
This means that animals have equal likelihood
The probability of seeing each animal
We have:
Blue fish = 3
Yellow fish = 7
Sea turtle = 1
Eels = 3
Express as probability
Blue fish = 3/14
Yellow fish = 7/14
Sea turtle = 1/14
Eels = 3/14
Express the fractions as decimals
Blue fish = 0.214
Yellow fish = 0.500
Sea turtle = 0.071
Eels = 0.214
So, their likelihoods are:
Blue fish = Equally likely
Yellow fish = Certainly likely
Sea turtle = Unlikely
Eels = Equally likely
Read more about probabilities at:
https://brainly.com/question/25870256
