Answer:
Step-by-step explanation:
h(t) = 841 - 16t
[Is this written correctly? The time is usually t^2, not t. I'll solve with the written equation, but check the equation]
The height at ground level is 0, so we want the value of t when h(t) = 0:
0 = 841 - 16t
-16t = -841
t = 53 seconds
One can also graph this formula and find the time to hit the ground at the point the line intersects the x axis (x = 0).
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If the equation should have read h(t) = 841 - 16t^2, solve it as above, setting h(t) = 0.
t = (29/4) seconds
This can also be graphed.
