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100 POINTS EZ |

The diagonal of a quadrilateral shaped field is 24 m and the perpendiculars dropped on it from the remaining opposite vertices are 8 m and 13 m. Find the area of the field.

100 POINTS EZ The diagonal of a quadrilateral shaped field is 24 m and the perpendiculars dropped on it from the remaining opposite vertices are 8 m and 13 m Fi class=

Respuesta :

  • Area of the quadrilateral=1/2×diagonal×(sum of perpendiculars)

Put the values

Area:-

[tex]\\ \rm\Rrightarrow \dfrac{1}{2}(24)(8+13)[/tex]

[tex]\\ \rm\Rrightarrow 12(21)[/tex]

[tex]\\ \rm\Rrightarrow 252m^2[/tex]

Answer:

Step-by-step explanation:

Divide the quadrilateral field into two triangles by its diagonal.

Area of a triangle is given by the equation 1/2*base*height.

The top triangle's area = 1/2*24*13 = 156 m^2

The bottom triangle's area = 1/2*24*8 = 96 m^2

Combining, the area of the field = 156 + 96 = 252 m^2

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