Respuesta :
By applying section formula we got that y-coordinate of the point that divides the directed line segment from J to K into a ratio of 5:1 is [tex]\frac{5y_2+y_1}{6}[/tex]
What is section formula ?
Let point P(x,y) cuts line joining point [tex]A(x_1,y_1)[/tex] and [tex]B(x_2,y_2)[/tex] in [tex]m_1:m_2[/tex] then coordinate of point P is equal to [tex](\frac{m_1x_2+m_2x_1}{m_1+m_2}, \frac{m_1y_2+m_2y_1}{m_1+m_2})[/tex]
Here given that point divides line segment from J to K into a ratio 5:1
So
[tex]m_1=5\\\\m_2=1[/tex]
Now we have to fin y coordinate of point that divides the directed line segment from J to K into a ratio of 5:1
We can calculated y coordinate by applying section formula as :
[tex]\frac{5y_2+1y_1}{5+1}\\\\\frac{5y_2+y_1}{6}[/tex]
By applying section formula we got that y-coordinate of the point that divides the directed line segment from J to K into a ratio of 5:1 is [tex]\frac{5y_2+y_1}{6}[/tex]
To learn more about section formula visit:https://brainly.com/question/26433769
