The energy that it takes to melt 2 kg of ice is; (2 kg * 1000 g/kg) * 1 mol/18.02 g * 6.03 kJ/mol = 669 kJ
What is the energy required?
We are given;
Mass of ice; m = 2 kg
Now, from tables showing constants for ice, we see that;
Molar heat of fusion for ice; Δ_fus.H = 6.03 kJ/mol at 0°C.
Molar mass of Ice which is water is; 18.02 g/mol
Formula to get the energy is;
E = (m/M) * Δ_fus.H
E = (2 kg * 1000 g/kg) * 1 mol/18.02 g * 6.03 kJ/mol = 669 kJ
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