Answer:
Tanisha = 14 years
Ana = 7 years
Elicia = 16 years
Step-by-step explanation:
Let T = age of Tanisha
Let A = age of Ana
Let E = age of Elicia
Tanisha is twice as old as Ana:
T = 2A
⇒ A = (1/2)T
Elicia is 2 years older than Tanisha:
E = 2 + T
Sum of all their ages is 37:
A + E + T = 37
Substitute A = (1/2)T and E = 2 + T into A + E + T = 37 and solve for T:
⇒ (1/2)T + 2 + T + T = 37
⇒ (5/2)T = 35
⇒ T = 14
If T = 14, then
A = (1/2)T = (1/2) 14 = 7
If T = 14, then
E = 2 + T = 2 + 14 = 16
